Sample Question

For his Physics class, Jeremy stood on the top of a building (which was 48 feet high) and threw a ball straight up into the air with an intial velocity of 32 ft. per second. The distance between the ball the ground below can be modeled with the equaiton h = -16t² + 32t + 48.

• When will the ball hit the ground?
• What is the highest point the ball will reach?
• When will the ball be 52 feet above the ground?

Sample Response

• The ball hits the ground at 3 seconds.
• It looks like at 1 second the height is the most at 64 feet.
• The table doesn't show 52 feet, but it will be between 1.75 and 2 seconds. I think it's probably about 1.8 seconds.